SSC CGL Quantitative Aptitude Questions with solutions PDF
The Staff Selection Commission (SSC) Combined Graduate Level (CGL) exam is one of the most competitive exams in India. One of the most challenging sections of this exam is the Quantitative Aptitude section, which tests the candidates’ knowledge of mathematics. In this blog post, we will provide some SSC CGL Quantitative Aptitude questions with solutions.
SSC CGL Quantitative Aptitude Questions with solutions PDF
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- Two trains start from two points A and B towards each other at the same time. The speed of the first train is 90 km/h and the speed of the second train is 120 km/h. If the distance between the two points is 1350 km, how long will it take for the two trains to meet?
Solution:
The two trains are moving towards each other. Therefore, the relative speed of the two trains is the sum of their speeds, i.e., 90 + 120 = 210 km/h.
The time taken for the two trains to meet is equal to the distance between the two points divided by their relative speed. Therefore,
Time taken = Distance / Relative speed = 1350 / 210 = 6.43 hours (approx.)
Therefore, it will take approximately 6.43 hours for the two trains to meet.
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- Find the value of x in the equation 3x + 7 = 22.
Solution:
We have the equation 3x + 7 = 22.
Subtracting 7 from both sides of the equation, we get:
3x = 22 - 7 3x = 15
Dividing both sides of the equation by 3, we get:
x = 5
Therefore, the value of x in the equation 3x + 7 = 22 is 5.
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- If a number is increased by 20% and then decreased by 20%, what is the net change in the number?
Solution:
Let the original number be x.
When the number is increased by 20%, the new number becomes 1.2x.
When the new number is decreased by 20%, the final number becomes 0.8(1.2x) = 0.96x.
Therefore, the net change in the number is:
0.96x - x = -0.04x
The net change is a decrease of 4% in the original number.
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SSC CGL Quantitative Aptitude Questions with solutions PDF
- A circular track has a circumference of 352 meters. If three cyclists start from the same point and ride in the same direction, starting at the same time, and their speeds are 8 m/s, 10 m/s and 12 m/s respectively, after how much time will they be together again at the starting point?
Solution:
The first cyclist covers one complete lap of the track in the time taken, t.
The second cyclist covers one complete lap of the track in the time taken, t - x, where x is the time taken for the first cyclist to complete one lap.
The third cyclist covers one complete lap of the track in the time taken, t - y, where y is the time taken for the first cyclist to complete two laps.
Since the circumference of the track is 352 meters, the distance covered by each cyclist in one lap is 352 meters.
Therefore, the time taken by each cyclist to cover one lap is:
Time taken = Distance / Speed
For the first cyclist, the time taken is:
t = 352 / 8 = 44 seconds
For the second cyclist, the time taken is:
t - x = 352 / 10 t - x = 35.2 seconds
For the third cyclist, the time taken is:
t - y = 352 / 12 t - y = 29.33 seconds
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