IBPS PO Quantitative Aptitude Questions with Answers pdf

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IBPS PO Quantitative Aptitude Questions with Answers pdf



IBPS PO is one of the most prestigious banking exams in India. Every year, thousands of candidates apply for this exam, hoping to land a job in the banking sector. One of the important sections of the IBPS PO exam is the Quantitative Aptitude section. This section tests the candidate's mathematical abilities and aptitude. In this blog post, we will be discussing some important IBPS PO Quantitative Aptitude questions with answers.


  1. A sum of Rs. 50,000 is invested for 2 years at the rate of 10% p.a. Find the simple interest earned.

Solution:

Simple Interest (SI) = (P * R * T) / 100 where P = principal amount, R = rate of interest, T = time period

Given, P = Rs. 50,000, R = 10% p.a., T = 2 years

SI = (50,000 * 10 * 2) / 100 = Rs. 10,000

Therefore, the simple interest earned is Rs. 10,000.



  1. A boat travels upstream at a speed of 10 km/hr and downstream at a speed of 20 km/hr. Find the speed of the stream if the speed of the boat in still water is 15 km/hr.

Solution:

Let the speed of the stream be x km/hr. Speed of the boat upstream = (15 - x) km/hr Speed of the boat downstream = (15 + x) km/hr

We know that speed = distance / time

Let the distance travelled be d km. Time taken upstream = d / (15 - x) hours Time taken downstream = d / (15 + x) hours

Total time taken = time taken upstream + time taken downstream = d / (15 - x) + d / (15 + x)

We also know that time taken upstream = time taken downstream Therefore, d / (15 - x) = d / (15 + x)

Simplifying the equation, we get: 225 - x^2 = 225 + x^2 2x^2 = 0 x^2 = 0 x = 0

Therefore, the speed of the stream is 0 km/hr.



  1. A man sells an article at a profit of 20%. If he had sold it for Rs. 300 more, he would have made a profit of 30%. Find the cost price of the article.

Solution:

Let the cost price of the article be x. Selling price with a profit of 20% = (120/100) * x = 1.2x

Selling price with a profit of 30% = (130/100) * x = 1.3x

Given, 1.3x - 1.2x = Rs. 300 0.1x = Rs. 300 x = Rs. 3,000

Therefore, the cost price of the article is Rs. 3,000.



  1. The length of a rectangle is twice its breadth. If the area of the rectangle is 288 sq.cm, find its length and breadth.

Solution:

Let the breadth of the rectangle be x. Length of the rectangle = 2x

Area of the rectangle = Length * Breadth 288 = 2x * x 288 = 2x^2 x^2 = 144 x = 12

Therefore, the breadth of the rectangle is 12 cm. Length of the rectangle = 2 * 12 = 24 cm.





















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